Pie chart from energy company:
This blog features information pertaining to topics covered in our Energy System Design class at the University of Iowa for the Fall semester of 2011. It is a collaboration between Matt Burke and Matt Mercer and will be focused around the theme of energy sustainability.
Tuesday, November 1, 2011
Part 2-4 Heating and Cooling Energy needs for the home
Qheat = (UA + mdot * Cpa) * HDD
Qcool, sensible = (UA + mdot * Cpa) * CDD
Qcool, latent = mdot * hfg * SUM(wb-wo)deltaT
= 67470199 Btu
Qcool, sensible = (UA + mdot * Cpa) * CDD
= [(146.76Btu/F*hr)+(211.8 lb/hr)*(0.2441Btu/lb*F)]*1270*day(24hr)
=6049072 Btu
Qcool, latent = mdot * hfg * SUM(wb-wo)deltaT
= (211.8 lb/hr)(970.34 Btu/lb)(22.48 hr) = 4620045 Btu
Qcool, sensible = (UA + mdot * Cpa) * CDD
Qcool, latent = mdot * hfg * SUM(wb-wo)deltaT
Cp=0.2441 Btu/lb
mdot=211.8 lb/hr
hfg=970.34 Btu/lb
Qheat = (UA + mdot * Cpa) * HDD
=[(337.24Btu/F*hr)+(211.8 lb/hr)*(0.2441Btu/lb*F)] * 7228F*day (24hr)= 67470199 Btu
Qcool, sensible = (UA + mdot * Cpa) * CDD
= [(146.76Btu/F*hr)+(211.8 lb/hr)*(0.2441Btu/lb*F)]*1270*day(24hr)
=6049072 Btu
Qcool, latent = mdot * hfg * SUM(wb-wo)deltaT
= (211.8 lb/hr)(970.34 Btu/lb)(22.48 hr) = 4620045 Btu
Part 2-3 Ventilation Rate of the Home
Assuming standard air exchange for homes, the ventilation rate was calculated as follows:
Desired air exchange rate = 0.35
8 ft ceilings
Ventilation rate = Volume*air exchange rate = (1000ft*8ft)(0.35/hr)(1hr/60min) = 46.67 cfm
or Q=mdot/density of air = (3.53 lb/min)/(0.0757lb/ft^3) @ 65 degrees F = 46.63 cfm
Desired air exchange rate = 0.35
8 ft ceilings
Ventilation rate = Volume*air exchange rate = (1000ft*8ft)(0.35/hr)(1hr/60min) = 46.67 cfm
or Q=mdot/density of air = (3.53 lb/min)/(0.0757lb/ft^3) @ 65 degrees F = 46.63 cfm
Part 2-2 Determine the heating and cooling degree days for a typical year
The heating degree days in Iowa City from 10/1/2010-09/1/2011 are shown below
The cooling degree days in Iowa City from 10/1/2010-09/1/2011 are shown below
Total heating degree days in a year in Iowa City = 7228
Totla cooling degree days in a year in Iowa City = 1270
Part 2-1 of project: R-values and overall thermal conductance of building materials
Part 2 of the project will consider a standard size (1000 sq. ft.), 2-bedroom, one story home with no basement. The group chose Iowa City as the location. (If you don't bleed black & gold...)
1. List the R-values of the building materials and compute the overall thermal conductance (UA) of the home.
When calculating the R-values of the building materials, some assumptions of the types of materials that were used had to be made. These are reflected in the table below
1. List the R-values of the building materials and compute the overall thermal conductance (UA) of the home.
When calculating the R-values of the building materials, some assumptions of the types of materials that were used had to be made. These are reflected in the table below
The overall thermal conductance was calculated using the general equation UA= (1/Rvalue)*(Area) for each total R-value and summing up those terms. The total R-values and total areas are shown in the table below.
*The floor of a slab home needs to be considered for sizing a furnace but not an air-conditioner.
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